(x^2-4x)^2+(x-2)^2=10

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Solution for (x^2-4x)^2+(x-2)^2=10 equation: 



(x^2-4x)^2+(x-2)^2=10

We move all terms to the left:

(x^2-4x)^2+(x-2)^2-(10)=0

We move all terms containing x to the left, all other terms to the right

(x^2-4x)^2+(x-2)^2=10

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